(1/3)^y=23^y+1

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Solution for (1/3)^y=23^y+1 equation: 



(1/3)^y=23^y+1

We move all terms to the left:

(1/3)^y-(23^y+1)=0



Domain of the equation: 3)^y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/3)^y-(23^y+1)=0

We get rid of parentheses

(+1/3)^y-23^y-1=0

We multiply all the terms by the denominator


(+1-23^y*3)^y-1*3)^y=0

Wy multiply elements

(+1-23^y*3)^y-3y=0

We add all the numbers together, and all the variables

-3y+(+1-23^y*3)^y=0

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